Let \(P_w(n)\) be the set of distinct subwords (intervals) in a word \(w\).
Let \(p_w(n)\) be the cardinality of \(P_w(n)\).
Let \(f(c)\) be the sequence in FASTA with 4-symbol Protein Data Bank code \(c\).
\(|P_{f(8YLT_1)}(2) \setminus P_{f(6OFT_1)}(2)|=92\),
\(|P_{f(6OFT_1)}(2) \setminus P_{f(8YLT_1)}(2)|=41\).
Let
\(
Z_k(x,y)=|P_x(k)\setminus P_y(k)|+|P_y(k)\setminus P_x(k)|
\)
be a LZ76 style (set of subwords) Jaccard distance numerator for \(P(k)\).Hydrophobic-polar version of Sequence 1:110101000001001001111100011001001000000101111111110010001011011000000101010010000000101101100101011101110011010010011000111101101100000011001010010010110100011010000011010101001101001110000010000001110011001110001111101110001011101100100001001111000101100001100000110110110110000000100001110111000000110000011001010101111100100101001100000101010110000011101001101000000000100000001011101100011101100110100010100110010001100110000101000000111110110100000100011100100001010010010000100010011001011111011000011000111010001001010011011110100000110110000110000101101000100010010001110001111101000101100001101010010001000101110010000000100111011100011110000110100010100100100000100101100001000111110010001010110111000110010111011001010001110110111101100010110001110010000011001101100111101000100000010001100000111100100011000100101010000000101110111110001000110100100100110110111100101000011100100001001100001100100000100111101100100001001111000001110100100001110110000001110111000100011011000100000000101110011
Let d be the
Otu--Sayood
distance d.
Let d1 be the Otu--Sayood distance d1. (This makes the 4TYN sequence AAAAAA a close match...)
A roughly speaking expected distance is \((0.85)(0.8)(\frac{1476
}{\log_{20}
1476}-\frac{471}{\log_{20}471})=256.\)
Status
Protein1
Protein2
d
d1/2
Query variables
8YLT_1
6OFT_1
321
235.5
Was not able to put for d Was not able to put for d1
In notation analogous to
[Theorem 16, Kjos-Hanssen, Niraula and Yoon (2022)],
\[
\delta=
\alpha \mathrm{min} + (1-\alpha) \mathrm{max}=
\begin{cases}
d &\alpha=0,\\
d_1/2 &\alpha=1/2
\end{cases}
\]